#P6073. 『MdOI R1』Epic Convolution
『MdOI R1』Epic Convolution
Description
Given specific sequences , compute satisfying .
This problem has five subtasks. The first four subtasks give different forms of and ask you to compute . The fifth subtask does not depend on this equation, but it looks similar in form.
Note: all outputs in this problem should be taken modulo (, a prime).
Subtask 1 (4 pts):
Given an integer , you need to answer queries. Each query gives an integer .
For each query, and are as follows ():
You need to output the value of .
Subtask 2, 3 (16, 16 pts):
These two subtasks use the same form of sequences , but have different constraints. Please read the constraints carefully.
You need to answer queries. Each query gives two integers .
For each query, and are as follows ():
$$h_k=\begin{cases}0,&k<m\\\frac{(-1)^{k-m}}{(k-m)!},&k\geq m\end{cases}$$You need to output the value of .
Subtask 4 (32 pts):
You need to answer queries. Each query gives two integers .
For each query, and are as follows ():
You need to output the value of .
Subtask 5 (32 pts):
You need to answer queries. Each query gives two integers .
Note the meaning of below. Do not swap them.
$$\sum\limits_{k=0}^{m}(k+1)^m\dfrac{(k+1)^{n+1}}{(k+1)!}\sum\limits_{i=0}^{m-k}\dfrac{\binom{2n+1}{i}(-1)^{m-k}}{(m-k-i)!(k+1)^i}$$You need to output the value of the expression above.
Similar to the first four subtasks, the summation starts with a power term.
Input Format
The first line contains an integer , indicating the subtask number.
If :
The second line contains an integer , and the third line contains an integer .
Then follow lines, each containing an integer .
If :
The second line contains an integer .
Then follow lines, each containing two integers .
The meaning of all variables is given in the problem description.
Output Format
For each query, output one integer per line, indicating the answer.
1
5
2
2
3
1
33
2
2
4 2
18 7
440891256
841247136
4
2
4 2
20 9
65
429844531
5
2
4 2
30 12
58
475486366
Hint
Sample Explanation 1
In this sample, you need to solve Subtask 1, with .
In the first query, , then (omitting terms whose addend is ):
$$[g_0\ \ g_1\ \ g_2\ \ g_3\ \ g_4\ \ g_5]=[1\ \ 1\ \ 0\ \ 0\ \ 0\ \ 0]$$$$[h_0\ \ h_1\ \ h_2\ \ h_3\ \ h_4\ \ h_5]=[1\ \ 1\ \ 1\ \ 1\ \ 1\ \ 1]$$In the second query, , then:
$$[g_0\ \ g_1\ \ g_2\ \ g_3\ \ g_4\ \ g_5]=[1\ \ 1\ \ 1\ \ 0\ \ 0\ \ 0]$$$$[h_0\ \ h_1\ \ h_2\ \ h_3\ \ h_4\ \ h_5]=[1\ \ 1\ \ 1\ \ 1\ \ 1\ \ 1]$$Sample Explanation 2
In this sample, you need to solve Subtask 2, with .
In the first query, , then:
$$[g_0\ \ g_1\ \ g_2\ \ g_3\ \ g_4]=[\dfrac{1}{6}\ \ \dfrac{1}{24}\ \ \dfrac{1}{120}\ \ \dfrac{1}{720}\ \ \dfrac{1}{5040}]$$$$[h_0\ \ h_1\ \ h_2\ \ h_3\ \ h_4]=[0\ \ 0\ \ 1\ \ -1\ \ \dfrac{1}{2}]$$$$f_4=1^4\times g_1h_3+2^4\times g_2h_2=\dfrac{11}{120}$$After taking modulo , equals .
The second query has constraints that are too large, so no sample explanation is provided.
Sample Explanation 3
In this sample, you need to solve Subtask 4, with .
In the first query, , then:
$$[g_0\ \ g_1\ \ g_2\ \ g_3\ \ g_4]=[0\ \ \ 1\ \ \ 2\ \ \ \dfrac{3}{2}\ \ \dfrac{2}{3}]$$$$[h_0\ \ h_1\ \ h_2\ \ h_3\ \ h_4]=[1\ \ -1\ \ \dfrac{1}{2}\ \ -\dfrac{1}{6}\ \ \dfrac{1}{24}]$$$$f_4=1^4\times g_1h_3+2^4\times g_2h_2+3^4\times g_3h_1+4^4\times g_4h_0=65$$The second query has constraints that are too large, so no sample explanation is provided.
Sample Explanation 4
In this sample, you need to solve Subtask 5, with .
In the first query, , enumerate :
$$k=0,\ \ i=0:\ \ (k+1)^m\dfrac{(k+1)^{n+1}}{(k+1)!}\dfrac{\binom{2n+1}{i}(-1)^{m-k}}{(m-k-i)!(k+1)^i}=\dfrac{1}{2}$$$$k=0,\ \ i=1:\ \ (k+1)^m\dfrac{(k+1)^{n+1}}{(k+1)!}\dfrac{\binom{2n+1}{i}(-1)^{m-k}}{(m-k-i)!(k+1)^i}=9$$$$k=0,\ \ i=2:\ \ (k+1)^m\dfrac{(k+1)^{n+1}}{(k+1)!}\dfrac{\binom{2n+1}{i}(-1)^{m-k}}{(m-k-i)!(k+1)^i}=36$$$$k=1,\ \ i=0:\ \ (k+1)^m\dfrac{(k+1)^{n+1}}{(k+1)!}\dfrac{\binom{2n+1}{i}(-1)^{m-k}}{(m-k-i)!(k+1)^i}=-64$$$$k=1\ \ i=1:\ \ (k+1)^m\dfrac{(k+1)^{n+1}}{(k+1)!}\dfrac{\binom{2n+1}{i}(-1)^{m-k}}{(m-k-i)!(k+1)^i}=-288$$$$k=2\ \ i=0:\ \ (k+1)^m\dfrac{(k+1)^{n+1}}{(k+1)!}\dfrac{\binom{2n+1}{i}(-1)^{m-k}}{(m-k-i)!(k+1)^i}=\dfrac{729}{2}$$Adding them all up gives .
The second query has constraints that are too large, so no sample explanation is provided.
Constraints
This problem uses bundled testdata, and different subtasks have different statements.
| Subtask ID | Points | |||
|---|---|---|---|---|
| 1 | 4 | |||
| 2 | 16 | |||
| 3 | ||||
| 4 (31-40) | 32 | |||
| 4 (51-60) | ||||
| 5 | ||||
All inputs are positive integers.
Translated by ChatGPT 5
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